Which one of the following ions has same number of unpaired electrons as that of $V^{3 +}$ ion?

C r^{3 +}

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M n^{2 +}

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N i^{2 +}

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F e^{3 +}

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Solution

The correct option is C $N i^{2 +}$
$V^{3 +} [A r] 3 d^{2}$ $[V : [A r] 3 d^{3} 4 s^{2}]$
$∴$ unpaired electron= 2
$C r^{3 +} [A r] 3 d^{3}$ $3^{r d}$ element of 3d series
$M n^{2 +} [A r] 3 d^{5}$
$N i^{2 +} [A r] 3 d^{8} \leftarrow 2 u n p a i r e d e l e c t r o n s$
$F e^{3 +} [A r] 3 d^{5}$

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Similar questions

Which of the following ion has same number of unpaired electrons as that of $V^{3 +}$ ion?

Question 14

The pair of ions having same electronic configuration is.............

(a) $C r^{3 +}, F e^{3 +}$ (b) $F e^{3 +}, M n^{2 +} +$ (c) $F e^{3 +}, C o^{3 +}$ (d) $S C^{3 +}, C r^{3 +}$

Write down the number of 3d electrons in each of the following ions:

Ti²⁺, V²⁺, Cr³⁺, Mn²⁺, Fe²⁺, Fe³⁺, CO²⁺, Ni²⁺ and Cu²⁺.

Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

[A r] 3 d^{10}

{C r}^{3 +}

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