Which one of the following ions is the most stable in aqueous solution?
(At. No. are: $T i = 22, V = 23, C r = 24, M n = 25$ )

M n^{3 +}

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C r^{3 +}

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V^{3 +}

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T i^{3 +}

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Solution

The correct option is C $C r^{3 +}$
In aqueous solution the configuration of the ions are following:

$C r^{3 +} (21) = 3 d^{3} 4 s^{0} \Rightarrow {t_{2 g}}^{3} e_{g}^{0}$

$V^{3 +} (20) = 3 d^{2} 4 s^{0} \Rightarrow {t_{2 g}}^{2} e_{g}^{0}$

$T i^{3 +} (19) = 3 d^{1} 4 s^{0} \Rightarrow {t_{2 g}}^{1} e_{g}^{0}$

$M n^{3 +} (22) = 3 d^{4} 4 s^{0} \Rightarrow {t_{2 g}}^{4} e_{g}^{0}$

We know that half-filled and fully filled orbitals are more stable than another half nor fully filled orbitals. Hence among the given ions the only ion which occupies half-filled $t_{2 g}$ orbitals is Chromium (III) ion.

$N o t e :$ Although $M n^{3 +}$ ion has half-filledr $t_{2 g}$ orbital but there is one more electron filled in $e_{g}$ orbital which reduces the stability.

Hence option A is the correct answer.

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Similar questions

Which one of the following ions is the most stable in aqueous solution?
(Atomic number. Ti = 22, V = 23, Cr = 24, Mn = 25)

3 d

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

T i = 22, V = 23, M n = 25, C r = 24)

M n^{3 +}, C r^{3 +}, V^{3 +}

T i^{3 +}

^{3 +}

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

(i) 2 M n O_{4}^{-} + 16 H^{+} + 5 S^{2 -} \to (i i) K M n O_{4} H e a t - -- \to

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

(i) 2 M n O_{4}^{-} + 16 H^{+} + 5 S^{2 -} \to (i i) K M n O_{4} H e a t - -- \to

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