The correct option is A 2xy
Given: 2x3y+4xy2+8xy.
Now, each term can be factorised as,
2x3y=2×x×x×x×y
4xy2=2×2×x×y×y
8xy=2×2×2×x×y
In above terms 2, x and y are the common terms.
So,
2x3y+4xy2+8xy
=2xy(x2+2y+4)
∴2xy is one of the factors of 2x3y+4xy2+8xy.