Question

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour?

• A. $\left[Zn\right(N{H}_3{)}_6{]}^{2+}$
• B. $\left[Zi\right(N{H}_3{)}_6{]}^{2+}$
• C. $\left[Cr\right(N{H}_3{)}_6{]}^{3+}$
• D. $\left[Co\right(N{H}_3{)}_6{]}^{3+}$

Answer 1

The correct option is D $\left[Co\right(N{H}_3{)}_6{]}^{3+}$

Orbitals in $C{o}^{+3}$ ion

$\uparrow \downarrow \uparrow \uparrow \uparrow \uparrow$

$3d$ $4s$ $4p$

Making Hybridized orbitals

$\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$

$d^{2}s{p}^3$

$\left[Co\right(N{H}_3{)}_6{]}^{3+}$

$\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$ $\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$

$6$ pairs of electrons from $6N{H}_3$ molecules.

Inner ${}^{\prime }{d}^{\prime }$ orbitals are used in hybridization so its inner orbital complex. There are no unpaired electrons so that it is dimagnetic.