Question

Which one of the following is correct order of the size of iodine species?

• A. $I>I^{–}>I^{+}$
• B. $I^{–}>I>I^{+}$
• C. $I^{+}>I^{–}>I$
• D. $I>I^{+}>I^{-}$

Answer 1

The correct option is B $I^{–}>I>I^{+}$

Positive ion is always smaller and negative ion is always larger than the parent atom. So, the correct order of the size of iodine species will be $I^{–}>I>I^{+}$