Which one of the following is more reactive toward $S N_{2}$ mechanism?

(C H_{3})_{3} C - B r

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(C H_{3})_{2} C H - B r

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C H_{3} - B r

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C_{2} H_{5} - (C H_{3}) C H - B r

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Solution

The correct option is D $C H_{3} - B r$
$C H_{3} - B r$ is more reactive towards $S N^{2}$ mechanism. $C H_{3} - B r$ is methyl halide. The order of reactivity towards $S N^{2}$ mechanism is methyl halide > primary alkyl halide > secondary alkyl halide > tertiary alkyl halide. $(C H_{3})_{3} C - B r$ is tertiary alkyl halide. $(C H_{3})_{2} C H - B r$ and $C_{2} H_{5} - (C H_{3}) C H - B r$ are secondary alkyl halides.

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Similar questions

C H_{3} - C H | C_{2} H_{5} - B r

C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

C_{2} H_{5} - C H | C_{2} H_{5} - C H_{2} B r

O H^{-}

C H_{3} - C H | C_{2} H_{5} - B r

C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

C H_{3} - C H | C_{2} H_{5} - C H_{2} B r

Predict the order of reactivity of the following compounds in SN1 and SN2 reactions

C6H5CH2Br , C6H5CH(C6H5)Br , C6H5CH(CH3)Br , C6H5C(CH3)(C6H5)

S_{N} 2

B r - C H_{2} - C H_{2} - B r

N = C - C H_{2} - B r

C H_{3} - C | B r H - C H_{3}

C H_{3} - C H_{2} - B r

Consider the reactions

(i) $(C H_{3})_{2} C H - C H_{2} B r C_{2} H_{5} O H - ---- \to (C H_{3})_{2} C H - C H_{2} O C_{2} H_{5} + H B r$

(ii) $(C H_{3})_{2} C H - C H_{2} B r C_{2} H_{S} O^{-} - ---- \to (C H_{3})_{2} C H C H_{2} O C_{2} H_{5} + B r^{-}$

The mechanism of reactions (i) & (ii) are respectively

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