Question

Which one of the following is most soluble?

• A. $\mathrm{CuS}(K_{\mathrm{sp}}=8\times {10}^{-37})$
• B. $MnS(K_{sp}=7\times {10}^{-16})$
• C. $B{i}_2{S}_3(K_{sp}=1\times {10}^{-70})$
• D. $A{g}_{2}S(K_{sp}=6\times {10}^{-51})$

Answer 1

Answer: (B)

$MnS(K_{sp}=7\times {10}^{-16})$

$K_{sp}$ is known as solubility product constant. It is the equilibrium between a solid & its respective ions in a solution. The value of the constants dentifies the degree of which the compound can dissociate in water.

Therefore, the higher the $K_{sp}$ the more soluble the compound is

$K_{sp}$ & $MnS$ higher compound to other to compounds.

Therefore, $MnS$ is the most soluble

Ans is $B\left)MnS\right(K_{sp}=7\times {10}^{-16})$