Which one of the following is not a quadratic equation $?$
i) $x^{2} = 6 x$
ii) $x^{2} - 6 x = 30$
iii) $x^{2} = 10$
iv) $x = 1$

Open in App

Solution

Given the equations are,
i) $x^{2} = 6 x$
ii) $x^{2} - 6 x = 30$
iii) $x^{2} = 10$ .
All of the equations are quadratic as all of the equations gives two roots.
But not the 4th one.
Its linear.

Suggest Corrections

Similar questions

(3 + 2 \sqrt{3})

x^{2} + 6 x - 3 = 0

x^{2} - 6 x - 3 = 0

x^{2} + 6 x + 3 = 0

x^{2} - 6 x + 3 = 0

x^{2} - 6 x + 6 = 0

x^{2} + 6 x - 6 = 0

x^{2} - 6 x - 6 = 0

x^{2} + 6 x + 6 = 0

\frac{2 x - 2}{x^{2} - 36} - \frac{x - 2}{x^{2} - 6 x} = \frac{x - 1}{x^{2} + 6 x}

x^{2} - 3 x + 2 = 0.

Join BYJU'S Learning Program