Which one of the following is not a reducing agent?

H_{2} S

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H_{2} T e

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H_{2} S e

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H_{2} O

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Solution

The correct option is C $H_{2} O$
A reducing agent must lose electron and make the other substance to get reduced(gain electrons).
But here $H_{2} O$ do not loose electrons as it has strong bonding between $O - H$ because of the less size of oxygen.
Hence option D is correct.

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Similar questions

H_{2} E

(E = O, S, S e, T e a n d P o

H_{2} S, H_{2} O, H_{2} S e, H_{2} T e

H_{2} S, H_{2} O, H_{2} S e, H_{2} T e

H_{2} O < H_{2} T e < H_{2} S e < H_{2} S

H_{2} O > H_{2} T e > H_{2} S e > H_{2} S

H_{2} O > H_{2} S > H_{2} S e > H_{2} T e

H_{2} O

H_{2} S

H_{2} S e

H_{2} T e

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