Which one of the following is not correct order of boiling points of the alkyl halides?

C H C l_{3} > C H_{2} C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} (C H_{2})_{3} C l > C H_{3} (C H_{2})_{2} C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(C H_{3})_{3} C C l > (C H_{3})_{2} C H C H_{2} C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} (C H_{2})_{3} C l > C H_{3} C H_{2} C H C l C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(C H_{3})_{3} C C l > (C H_{3})_{2} C H C H_{2} C l$
Intermolecular forces of attractions increases as molecular mass increases. So, large amount of heat require to break strong intermolecular forces and thus boiling point increases.

a) boiling point of $C H C l_{3}$ is more than $C H_{2} C l_{2}$ because $C H C l_{3}$ has more molecular mass than $C H_{2} C l_{2} .$

Intermolecular forces of attractions increases as molecular size increases. So, large amount of heat require to break strong intermolecular forces and thus boiling point increases.
boiling point of $C H_{3} (C H_{2})_{3} C l$ is more than $C H_{3} (C H_{2})_{2} C l$ because molecular size of $C H_{3} (C H_{2})_{2} C l$ is larger than $C H_{3} (C H_{2})_{3} C l$
Similarly, $C H_{3} C H_{2} C H C l C H_{2} C H_{3} > C H_{3} (C H_{2})_{3} C l$

Boiling point of isomeric haloalkanes decreases with increase in branching because surface area of molecule decreases due to which intermolecular forces of attraction decrease and hence boiling point decreases.
Boiling point of $(C H_{3})_{3} C C l$ is less than $(C H_{3})_{2} C H C H_{2} C l$ as former is more branched.

Hence, the correct answer is option (c).

Suggest Corrections

Similar questions

For the same alkyl group, the boiling point of alkyl halides decrease in the order:

R I > R B r > R C l > R F

Join BYJU'S Learning Program