Which one of the following is not the correct representation?

E_{c e l l}^{\circ} =

Red. pot. of cathode

+

Oxid. pot. of anode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{c e l l}^{\circ} =

Red. pot. of cathode

-

Oxid. pot. of anode

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

E_{c e l l}^{\circ} =

Red. pot. of cathode

-

Red. pot. of anode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{c e l l}^{\circ} =

Oxid. pot. of cathode

+

Oxid. pot. of anode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $E_{c e l l}^{\circ} =$ Red. pot. of cathode $-$ Oxid. pot. of anode
we have,
$E_{c e l l}^{0}$ = red. potential of cathode + oxidation potential of anode
so, option B is incorrect representation of $E_{c e l l}^{0}$

Suggest Corrections

Similar questions

E_{c e l l}^{0} = E_{r e d (c a t h o d e)}^{0} + E_{o x d (a n o d e)}^{0}

(E_{c e l l}^{\circ}) =

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Join BYJU'S Learning Program