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Octet Rule

Which one of ...

Question

Which one of the following is the correct order for the bond energies of halogen molecules?

C l_{2} > B r_{2} > I_{2}

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B r_{2} > C l_{2} > l_{2}

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l_{2} > C l_{2} > B r_{2}

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I_{2} > B r_{2} > C l_{2}

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Solution

The correct option is D $C l_{2} > B r_{2} > I_{2}$
Bond energy is inversely proportional to molecular mass as van der wall forces exist between molecules of halogens
$∴$ Bond Energy order:
$C l_{2} > B r_{2} > I_{2}$

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The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

C l_{2} > B r_{2} > F_{2} > I_{2}

{C l}_{2}, {B r}_{2}

I_{2}

F_{2}, C l_{2}, B r_{2}, I_{2}

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