Question

Which one of the following is the correct set with respect to molecule, hybridization and shape?

• A. $BeC{l}_2,s{p}^2$, linear
• B. $BeC{l}_2,s{p}^2$, triangular planar
• C. $BC{l}_3,s{p}^2$, triangular planar
• D. $BC{l}_3,s{p}^3$, tetrahedral

Answer 1

Answer: (C)

$BC{l}_3,s{p}^2$, triangular planar

In $BC{l}_3$, boron is $s{p}^2$ hybridised as there are $3$ bond pairs and $0$ lone pairs and thus, $BC{l}_3$ is triangular planar is shape.