Which one of the following is the orthocentre of the triangle whose sides are $x = 0, y = 1$ , and $x + y - 2 = 0$ ?

(1, 1)

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(0, 1)

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(- 1, 0)

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(0, - 1)

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Solution

The correct option is B $(0, 1)$
As The triangle formed by the lines x=0,y+1 and x+y-2=0

Since the line x=0 and y=1 intersect each other at right angle

So orthocenter of triangle is (0,1).

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Which one of the following is the orthocentre of the triangle whose sides are x=0,y=1, and x+y−2=0?

The correct option is B (0,1)As The triangle formed by the lines x=0,y+1 and x+y-2=0Since the line x=0 and y=1 intersect each other at right angleSo orthocenter of triangle is (0,1).

Which one of the following is the orthocentre of the triangle whose sides are $x = 0, y = 1$ , and $x + y - 2 = 0$ ?

The correct option is B $(0, 1)$
As The triangle formed by the lines x=0,y+1 and x+y-2=0

Since the line x=0 and y=1 intersect each other at right angle

So orthocenter of triangle is (0,1).