Which one of the following is the rational number lying between $\frac{6}{7} a n d \frac{7}{8} ?$

\frac{3}{4}

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\frac{99}{122}

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\frac{95}{112}

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\frac{97}{112}

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Solution

The correct option is C $\frac{97}{112}$
Required rational number $= \frac{1}{2} (\frac{6}{7} + \frac{7}{8}) = \frac{1}{2} (\frac{48 + 49}{56}) = \frac{97}{112}$
Hence option (d) is correct

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11^{2}

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