Which one of the following is true for any two square matrices A and B of same order?

(A B)^{T} = A^{T} B^{T}

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(A^{T} B)^{T} = A^{T} B^{T}

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(A B)^{T} = B A

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(A B)^{T} = B^{T} A^{T}

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Solution

The correct option is D $(A B)^{T} = B^{T} A^{T}$
$A ξ B$ are two square matrices, then $(A B)^{T} = B^{T} . A^{T} .$
Hence, the answer is $(A B)^{T} = B^{T} A^{T} .$

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