Which one of the following leads to third line of Balmer spectrum from red end (For hydrogen atom)?

2 ⟶ 5

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5 ⟶ 2

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3 ⟶ 2

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4 ⟶ 1

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Solution

The correct option is A $5 ⟶ 2$
The transition $5 ⟶ 2$ leads to third line of Balmer spectrum from red end (for hydrogen atom).
The transition $4 ⟶ 2$ leads to second line of Balmer spectrum from red end (for hydrogen atom).
The transition $3 ⟶ 2$ leads to first line of Balmer spectrum from red end (for hydrogen atom).
Balmer series corresponds to transitions to $n = 2$ level. The spectral lines belongs to visible region.

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Similar questions

In Balmer series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of th e following inner orbit jumps of the electron for bohr orbits in an atom of hydrogen?

A.3->2

B. 5->2

C. 4->1

D. 2->5

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Q. Assertion :For Balmer series of hydrogen spectrum, the value

n_{1} = 2

and

n_{2} = 3, 4, 5

. Reason: The value of n for a line in Balmer series of hydrogen spectrum having the highest wave length is

4

and

6

Q. In Bohr series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of the following inter - orbit jumps of the electron for Bohr orbits in an atom of hydrogen ?

Q. In hydrogen spectrum, the third line from the red end corresponds to which one of the following inter-orbit jumps of the electrons from Bohr orbit of hydrogen?

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