Question

Which one of the following ligands forms a chelate ring?

• A. Acetate
• B. Oxalate
• C. Cyanide
• D. Ammonia

Answer 1

Answer: (B)

Oxalate

$\bullet$ Acetate is $H_{3}C-C=\stackrel{\bullet \bullet }{O_{\bullet }^{\bullet }}$ . It doesnot form a ring because ring formed will be of 4 members which is unstable.

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$O^{\ominus }$

$\bullet$ Oxalate is . It is a bidentate ligand hence forms a chelate.

$\bullet$ Cyanide is $C{N}^{\ominus }$. It is a mono dentate ligand and hence it does not form chelate.

$\bullet$ Ammonia is $N{H}_3$. It is a mono dentate ligand and hence it does not form chelate.

Hence, Option "B" is the correct answer.