Which one of the following numbers is not a complete cube?

64

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216

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343

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256

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Solution

The correct option is C $256$
Prime factorization of:
$64 = 2^{6}$
$216 = 2^{3} \times 3^{3}$
$343 = 7^{3}$
$256 = 2^{8}$ .

We know, a perfect cube has multiples of $3$ as powers of prime factors.

Here, $256$ is not a perfect/complete cube.
Hence, option $D$ is correct.

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Similar questions

Q. In the following, which is the cube of odd natural number:

8, 64, 216, 343

Question 7
The lateral surface area of a cube is $256 m^{2}$ . The volume of the cube is:

A) $512 m^{3}$
B) $64 m^{3}$
C) $216 m^{3}$
D) $256 m^{3}$

Q. Mark (✓) against the correct answer
Which of the following is a cube of an odd number?
(a) 216
(b) 512
(c) 343
(d) 1000

Find the cube-roots of:

(i) $\frac{27}{64}$ (ii) $\frac{125}{216}$ (iiii) $\frac{343}{512}$

(iv) $64 \times 729$ (v) $64 \times 27$ (vi) $729 \times 8000$

(vii) $3375 \times 512$

Q. Which of the following numbers are not perfect cubes?

216

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Which one of the following numbers is not a complete cube?

The correct option is C 256Prime factorization of:64=26216=23×33343=73256=28.We know, a perfect cube has multiples of 3 as powers of prime factors.Here, 256 is not a perfect/complete cube.Hence, option D is correct.

The correct option is C $256$
Prime factorization of:
$64 = 2^{6}$
$216 = 2^{3} \times 3^{3}$
$343 = 7^{3}$
$256 = 2^{8}$ .

We know, a perfect cube has multiples of $3$ as powers of prime factors.

Here, $256$ is not a perfect/complete cube.
Hence, option $D$ is correct.