    Question

# Which one of the following options is CORRECT given three positive integers x, y and z, and a predicate P(x)=⇁(x=1)∧∀y(∃z(x=y∗z)) ⇒(y=x)∨(y=1)

A
(P(x) being true means that x is a prime number
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B
P(x) being true means that x is a number other than 1
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C
P(x) is always true irrespective of the value of x
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D
P(x) being true means that x has exactly two factors other than 1 and x
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Solution

## The correct option is A (P(x) being true means that x is a prime number If P(x) is true, then x≠1 and also x is broken into two factors, only if, one of the factors is x itself and other factor is 1, which is exactly the definition of a prime number. So P(x) is true means x is a prime number.  Suggest Corrections  0      Similar questions
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