Which one of the following options is the same as [5−1+10−1+2−2]−1?
A
1120
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B
2011
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C
45
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D
54
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Solution
The correct option is B2011 Using the law of exponents, for a non-zero integer a and an integer m, we have a−m=1am. ∴[5−1+10−1+2−2]−1=(15+110+122)−1=(4+2+520)−1=(1120)−1 Now, (1120)−1=11120=2011. Hence, [5−1+10−1+2−2]−1=2011.