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Bond Order and Enthalpy

Which one of ...

Question

Which one of the following order is correct for the bond energies?

I_{2} > {C l}_{2} > B r_{2}

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B r_{2} > {C l}_{2} > I_{2}

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I_{2} > B r_{2} > {C l}_{2}

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{C l}_{2} > B r_{2} > I_{2}

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Solution

The correct option is D ${C l}_{2} > B r_{2} > I_{2}$
Bond energy is inversely proportional to bond length.

Higher the bond length, less is the bond energy. The order of bond length is $I_{2}$ > ${B r}_{2}$ > ${C l}_{2}$ .

$∴$ Bond energy order $C l_{2} > B r_{2} > I_{2}$ .

Hence, option D is correct.

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Similar questions

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

{C l}_{2}, {B r}_{2}

I_{2}

F_{2}, C l_{2}, B r_{2}, I_{2}

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

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