The correct option is C B<Be<O<N
First ionisation energy increases in a period.
Thus, the first IE of the elements of the second period should be as follows Be<B<N<O
But in practice, the elements do not follow the above order. The first IE of these elements is B<Be<O<N
The lower IE of B than that of Be is because in B(1s2,2s2,2p2), electron is to be removed from 2p which is easy while in Be(1s2,2s2), electron is to be removed from 2s which is difficult. The low IE of O than that of N is because of the half-filled 2p orbitals in N(1s2,2s2,2p3).