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Question

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?

A
Br2>I2>F2>Cl2
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B
F2>Cl2>Br2>I2
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C
I2>Br2>Cl2>F2
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D
Cl2>Br2>F2>I2
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Solution

The correct option is D Cl2>Br2>F2>I2
The order of bond dissociation enthalpy is :
Cl2>Br2>F2>I2

As you go down the group the bond dissociation enthalpy should decrease, the only anomaly being Fluorine due to its small size.
Two fluorine atoms must come together to share a pair, but these many electrons concentrated on two small nuclei and separated over comparatively a very small distance repel each other.

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