Question

Which one of the following pairs of chemical species contains the ions having same hybridisation of the central atoms?

• A. $N{O}_2^{-}$ and $N{H}_2^{-}$
• B. $N{O}_2^{-}$ and $N{H}_3^{-}$
• C. $N{O}_2^{-}$ and $N{O}_3^{-}$
• D. $SC{N}^{-}$ and $N{H}_2^{-}$

Answer 1

The correct option is C

$N{O}_2^{-}$ and $N{O}_3^{-}$

$H=\frac{1}{2}[V+M-C+A]$

Where H = hybridisation, V = valence electrons, M = Ligands, A = Negative charge, C = Positive charge

For $N{O}_2^{-}$ $H=\frac{1}{2}[5+0-0+1]=\frac{6}{2}=3$ $s{p}^2$

For $N{O}_3^{-}$ $H=\frac{1}{2}[5+0-0+1]=\frac{6}{2}=3$

Same hybridisation $s{p}^2$. In the above formulae, we take the ligands to be 0 because thr central atom is bonded to oxygen - an exception in this case.