Question

Which one of the following pairs of ions cannot be separated by $H_{2}S$ in $dil.HCl$?

• A. $B{i}^{3+}$, $S{n}^{4+}$
• B. $A{l}^{3+}$, $H{g}^{2+}$
• C. $C{u}^{2+}$, $Z{n}^{2+}$
• D. $N{i}^{2+}$, $C{u}^{2+}$

Answer 1

The correct option is A $B{i}^{3+}$, $S{n}^{4+}$

Option (A) is correct.
$B{i}^{3+}$, $S{n}^{4+}$ cannot be separated by $H_{2}S$ in $dil.HCl$ as both the cations belong to second group.