Which one of the following pairs of ions have the same electronic configuration?

C r^{3 +}, F e^{3 +}

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F e^{3 +}, M n^{2 +}

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F e^{3 +}, C o^{3 +}

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S c^{3 +}, C r^{3 +}

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Solution

The correct option is B $F e^{3 +}, M n^{2 +}$
$F e^{3 +}, M n^{2 +}$ shows same electronic configuration viz. $[A r] 3 d^{5} 4 s^{0}$

Remaining transition elements exhibit same electronic configuration in following oxidation state:

$S c^{3 +}, C r^{6 +} = [A r],$

$M n^{2 +}, F e^{3 +}, C o^{4 +}, C r^{+} = [A r] 4 s^{0} 3 d^{5}$

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Question 14

The pair of ions having same electronic configuration is.............

(a) $C r^{3 +}, F e^{3 +}$ (b) $F e^{3 +}, M n^{2 +} +$ (c) $F e^{3 +}, C o^{3 +}$ (d) $S C^{3 +}, C r^{3 +}$

F e^{2 +}, F e^{3 +}, C r^{2 +}, C r^{3 +}, M n^{2 +}, M n^{3 +}

F e^{2 +}, F e^{3 +}, C r^{2 +}, C r^{3 +}, M n^{2 +}, M n^{3 +}

C r^{3 +}

F e^{3 +}

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

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