Which one of the following reaction is expected to readily give a hydrocarbon product in good yields?

R C O O K o x i d a t i o n - ------ \to E l e c t r o l y t i c

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R C O O^{-} A g_{2}

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{C H}_{3} {C H}_{3} h u - - \to {C l}_{2}

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({C H}_{3})_{3} C C I C_{2} H_{5} O H ⟶

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Solution

The correct option is A $R C O O K o x i d a t i o n - ------ \to E l e c t r o l y t i c$
The Kolbe reaction is formally a decarboxylative dimerisation of two carboxylic acids (or carboxylate ions). The overall reaction is:
$2 R C O O K - 2 e^{-} - 2 C O_{2} - --- \to R - R$

Hence option (A) is correct.

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Similar questions

C H_{3} - C H_{3} | C H - C H_{3}

B r_{2} h v - \to C H_{3} - C H_{3} | C | B r - C H_{3} + C H_{3} - C H_{3} | C H - C H_{2} - B r

1^{o} H, 2^{o} H

3^{o} H

{C H}_{3} - C H = {C H}_{2} + H B r ⟶ {C H}_{3} C H_{2} {C H}_{2} B r (A) + {C H}_{3} - C H | B r - C H_{3} (B)

In the reaction $C H_{3} - C H_{3} | C H - C H_{2} O - C H_{2} - C H_{3} + h e a t e d H I \to . . . . . . . . . .$

Which of the following compounds will be formed?

C H_{3} - C H = C H - C H_{3} + B r_{2} / H_{2} O a q . N a c l ⟶

C H_{3} - C H_{3} | C | - C H_{3} C H_{2} C H_{2} O H K_{2} C r_{2} O_{7}; H_{2} S O_{4} - --------- \to H_{2} O h e a t A S O C l_{2} - --- \to B (C H_{3})_{2} N H - ------ \to (2 m o l e) C 1. L i A l H_{4} d i e t h y l e t h e r - ------------ \to 2. H_{2} O D

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