The reaction in which change in oxidation numbers of some of the atoms takes place is termed as a redox reaction.
(a) +2+6−2CuSO4+−3+14NH3→[+2Cu(−3N+1H3)4]+6S−2O4
No change in oxidation number of any of the atoms.
(b) +1Na2+6S−2O4++2Ba−1Cl2→+2Ba+6S−2O4++12Na−1Cl
No change in oxidation number of any one of the atoms.
(c) +4S−2O2++1H2−2O→+1H2+4S−2O3
No change in oxidation number of any one of the atoms.
(d) +22Cu+6S−2O4++14K−1I→+1Cu2−1I2++12K2+6S−2O4+0I2.
Oxidation number of Cu decreases from +2 to +1 and oxidation number of iodine increases from −1 to 0.
Thus, out of the above four reactions, the reaction (d) is a redox reaction.