Which one of the following represents the correct dimensions of the coefficient of viscosity?

[M L^{- 1} T^{- 1}]

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[M L T^{- 1}]

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[M L^{- 1} T^{- 2}]

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[M L^{- 2} T^{- 2}]

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Solution

The correct option is A $[M L^{- 1} T^{- 1}]$
From Stokes' law: $F_{d} = 6 π η R v$
$η = \frac{F_{d}}{6 π R v} = \frac{M L T^{- 2}}{(L) (L T^{- 1})} = M L^{- 1} T^{- 1}$

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Similar questions

\begin{matrix} List I(Physical quantity) & List II (Dimensions) A. Force & {1. T}^{- 1} B. Angular velocity & {2. MLT}^{- 2} C. Torque & {3. ML}^{- 1} T^{- 2} D. Stress & {4. ML}^{- 1} T^{- 1} {5. ML}^{2} T^{- 2} \end{matrix}

[M L^{- 1} T^{- 1}]

X

= \sqrt{(\frac{X}{density})}

X

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