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Coefficient of Viscosity

Which one of ...

Question

Which one of the following represents the correct dimensions of the coefficient of viscosity ?

A

{M L}^{- 1} T^{2}

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B

{M L T}^{- 1}

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C

{M L}^{- 1} T^{- 1}

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D

{M L}^{- 2} T^{- 2}

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Solution

The correct option is A ${M L}^{- 1} T^{- 1}$
For calculating coefficient of viscosity we can use the formula, $F = \frac{η v A}{S}$
Dimension of coefficient of viscosity will be $= \frac{D i m e n s i o n o f f o r c e \times D i s t a n c e}{V e l o c i t y \times A r e a}$

$= \frac{M L T^{- 2} \times L}{L T^{- 1} L^{2}}$

$= M L^{- 1} T^{- 1}$

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Similar questions

Q. Match List I with List II and select the correct answer using the codes given the lists.

List I	List II
P. Boltzmann Constant	$1$ . $[M L^{2} T^{- 1}]$
Q. Coefficient of viscosity	$2$ . $[M L^{- 1} T^{- 1}]$
R. Plank Constant	$3$ . $[M L T^{- 3} K^{- 1}]$
S. Thermal conducivity	$4$ . $[M L^{2} T^{- 2} K^{- 1}]$

Q. A physical quantity

X

is expressed as velocity

= \sqrt{(\frac{X}{density})}

. The dimensions of

X

Q. The dimension ML⁻¹T⁻² can correspond to
(a) moment of a force
(b) surface tension
(c) modulus of elasticity
(d) coefficient of viscosity

Q. Match the physical quantities given in Column I with suitable dimensions expressed in Column II.

Column I	Column II
a) Angular momentum	1) $M^{- 1} L^{3} T^{- 2}$
b) Torque	2) ${M L T}^{- 2}$
c) Gravitational constant	3) ${M L}^{2} T^{- 2}$
d) Tension	4) ${M L}^{2} T^{- 1}$

Q. What are the dimensions of

a

b

in the relation

F = a \sqrt{x} + b t^{2}

F

x

is distance and

t

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