Which one of the following represents the reaction between fluorine and cold dilute NaOH ?

2 F_{2} + 4 N a O H \to 4 N a F + 2 H_{2} O

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3 F_{2} + N a O H \to 5 N a F + N a F O_{3}

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F_{2} + 2 N a O H \to N a F + N a O F + H_{2} O

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2 F_{2} + 2 N a O H \to 2 N a F + O F_{2} + H_{2} O

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Solution

The correct option is D $2 F_{2} + 2 N a O H \to 2 N a F + O F_{2} + H_{2} O$
$2 F_{2} + N a O H \to 2 N a F + O F_{2} + H_{2} O$
$F_{2}$ is strong oxidising agent so it oxides ozygen and forms $O F_{2}$

Option D is correct.

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(Cold & dilute)

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