Which one of the following set of quantum numbers is not possible for a 4p electron?

n = 4, l = 1, m = - 1, s = + \frac{1}{2}

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n = 4, l = 1, m = 0, s = + \frac{1}{2}

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n = 4, l = 1, m = 2, s = + \frac{1}{2}

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n = 4, l = 2, m = - 1, s = + \frac{1}{2}

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Solution

The correct option is C $n = 4, l = 1, m = 2, s = + \frac{1}{2}$
For an orbital,
Principal quantum number $= n$ ,
$0 \leq l < n$
$- l \leq m \leq l$ .
For 4p orbital $n = 4, l = 1 \neq 2$ .

So, C is the correct option.

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Similar questions

Which set of quantum numbers is possible for the last electron of Mg⁺ ion?

n = 4, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{1} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 3, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 1, m_{1} = - 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

4 f -

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

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