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Question

Which one of the following shows maximum paramagnetic character?

A
[Fe(CN)6]3
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B
[Fe(CN)6]4
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C
[Cr(H2O)6]3+
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D
[Cu(H2O)6]2+
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Solution

The correct option is A [Fe(CN)6]3
(i) [Fe(CN)6]3

Here, oxidation state of Fe=+3

Electronic configuration of Fe (ground state) =[Ar]3d64s2

Electronic configuration of Fe (excited state) =[Ar]3d54s0

Number of unpaired electrons =5

(ii) [Fe(CN)6]4

Here, oxidation state of Fe=+2

Electronic configuration of Fe (ground state) =[Ar]3d64s2

Electronic configuration of Fe (excited state) =[Ar]3d64s0

Number of unpaired electrons =4

(iii) [Cr(H2O)6]3+

Here, oxidation state of Cr=+3

Electronic configuration of Cr3+=[Ar]3d34s0

Number of unpaired electrons =3

(iv) [Cu(H2O)6]2+

Here, oxidation state of Cu=+2

Electronic configuration of Cu2+=[Ar]3d94s0

Number of unpaired electrons =1

A number of unpaired electrons present is directly proportional to a paramagnetic character.

So, [Fe(CN)6]3 has maximum paramagnetic character.

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