Which one of the following shows maximum paramagnetic character?

{[F e {(C N)}_{6}]}^{3 -}

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{[F e {(C N)}_{6}]}^{4 -}

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{[C r {(H_{2} O)}_{6}]}^{3 +}

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{[C u {(H_{2} O)}_{6}]}^{2 +}

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Solution

The correct option is A ${[F e {(C N)}_{6}]}^{3 -}$
(i) $[F e (C N)_{6}]^{3 -}$

Here, oxidation state of $F e = + 3$

Electronic configuration of $F e$ (ground state) $= [A r] 3 d^{6} 4 s^{2}$

Electronic configuration of $F e$ (excited state) $= [A r] 3 d^{5} 4 s^{0}$

Number of unpaired electrons $= 5$

(ii) $[F e (C N)_{6}]^{4 -}$

Here, oxidation state of $F e = + 2$

Electronic configuration of $F e$ (ground state) $= [A r] 3 d^{6} 4 s^{2}$

Electronic configuration of $F e$ (excited state) $= [A r] 3 d^{6} 4 s^{0}$

Number of unpaired electrons $= 4$

(iii) $[C r (H_{2} O)_{6}]^{3 +}$

Here, oxidation state of $C r = + 3$

Electronic configuration of $C r^{3 +} = [A r] 3 d^{3} 4 s^{0}$

Number of unpaired electrons $= 3$

(iv) $[C u (H_{2} O)_{6}]^{2 +}$

Here, oxidation state of $C u = + 2$

Electronic configuration of $C u^{2 +} = [A r] 3 d^{9} 4 s^{0}$

Number of unpaired electrons $= 1$

A number of unpaired electrons present is directly proportional to a paramagnetic character.

So, $[F e (C N)_{6}]^{3 -}$ has maximum paramagnetic character.

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Similar questions

[Fe(H₂O)₆]³⁺ is strongly paramagnetic whereas [Fe(CN)₆]³⁻ is weakly paramagnetic. Explain.

[F e (C N)_{6}]^{3 -}

[F e (H_{2} O)_{6}]^{3 +}

[F e (C N)_{6}]^{- 4}, P O_{4}^{- 3}, S O_{4}^{- 2}, C l^{-}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{4 -}

E^{\circ}

[F e (C N)_{4}]^{4^{-}} \to [F e (C N)_{6}]^{3 -} + e^{-}

\begin{matrix} E^{\circ} = - 0.35 V F e^{2 +} \to F e^{3 +} + e^{-} & E^{\circ} = - 0.77 V \end{matrix}

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