Which one of the following statement is not true regarding $B_{2} H_{6}$ ?

It react with

N a H

to form

N a B H_{4}

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It is highly inflamable gas

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It contain four equal

B - H

bonds

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It react with lewis base to form always adduct

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Solution

The correct option is B It contain four equal $B - H$ bonds
$B_{2} H_{6}$ + $2 N a H$ $\to$ $2 N a (B H_{4})$
It is highly Inflamable Gas and it reacts with Lewis base to form always adduct
It Doesn't contain 4 equal B-H bonds
So Option C is correct.

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Similar questions

Which one of the following reacts with $B C l_{3}$ to form $B_{2} H_{6}$ ?

N H_{2} O H

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