The correct option is B The pH of 1×10−8M HCl is 8
a) pH+pOH=14 for all aqueous solutions at 25oC
b) pH of an acidic solution should be less than 7. The reason is that from H2O, [H+]=10−7M cannot be neglected in comparison to 10−8M.
The pH can be calculated as:
from acid, [H+]=10−8M.
from H2O,[H+]=10−7M
∴ Total [H+]=10−8+10−7
Total [H+]=10−8(1+10)
Total [H+]=11×10−8
∴pH=−log[H+]=−log(11×10−8)
pH=−[log11+8 log 10]
pH=−[1.0414−8]
pH=6.9586
c) The conjugate base of H2PO−4 is HPO2−4.