Question

Which one of the following will have largest number of atoms?

• A. $1g$ $Au$
• B. $1g$ $Na$
• C. $1g$ $Li$
• D. $1g$ ${Cl}_2$

Answer 1

The correct option is C $1g$ $Li$

(i) $1g$ $Au=\frac{1}{197}$ mol atom of $Au$
$=\frac{1}{197}\times 6.022\times {10}^{23}$ atoms of $Au$

(ii) $1g$ $Na=\frac{1}{23}$ mol atom of $Na$
$=\frac{1}{23}\times 6.022\times {10}^{23}$ atom of $Na$

(iii) $1g$ $Li=\frac{1}{7}$ mol atom of $Li$
$=\frac{1}{7}\times 6.022\times {10}^{23}$ atom of $Li$

(iv) $1g$ ${Cl}_2=\frac{1}{71}$ mol molecules of ${Cl}_2$
$=\frac{1}{71}\times 6.022\times {10}^{23}$ molecules of ${Cl}_2$

$=\frac{2}{71}\times 6.022\times {10}^{23}$ atoms of ${Cl}_2$

Hence, $1g$ lithium has the largest number of atoms.