Question

Which one of the following will have the largest number of atoms?

• A. 1 g Au(s)
• B. 1 g Na(s)
• C. 1 g Li(s)
• D. 1 g ${\mathrm{Cl}}_2$(s)

Answer 1

The correct option is C

1 g Li(s)

Part 1: Explanation for correct answer:-

Option (C) 1 g Li(s):-

The atomic mass of Lithium is 7

The number of atoms is $\frac{6.022\times {10}^{23}}{7}atoms$

Hence it is the correct option.

Part 2: Explanation for incorrect answers:-

Option (A) 1 g Au(s)

Atomic mass of silver is 197

Number of atoms is $\frac{6.022\times {10}^{23}}{197}atoms$

Hence incorrect option.

Option (B) 1 g Na(s)

Atomic mass of sodium is 23

Number of atoms is $\frac{6.022\times {10}^{23}}{23}atoms$

Hence incorrect option.

Option (D) 1 g ${\mathrm{Cl}}_2$(s)

Atomic mass of chlorine is 35.5

Number of atoms is $\frac{2\times 6.022\times {10}^{23}}{71}atoms$

Hence incorrect option.

Therefore, the largest number of atoms is option (C) 1 g Li(s)