Which one of the following will have the largest number of atoms? (Molar mass of Au=197g/mol)
A
1gAu(s)
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B
1gNa(s)
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C
1g of Li(s)
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D
1g of Cl2(g)
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Solution
The correct option is C1g of Li(s) The number of atoms can be calculated as (a)1gAu=1197×6.022×1023=6.022197×1023 (b)1gNa=6.02223×1023 (c)1gLi=6.0227×1023 (d)1gCl2=2×6.022×102371=6.02235.5×1023 1g of Li contains largest number of atoms.