Question

Which one of the four interchanges in signs and numbers would make the given equation correct? 6 $\times$ 4 + 2 = 16

• A. + and $\times$, 2 and 4
• B. + and $\times$, 2 and 6
• C. + and $\times$, 4 and 6
• D. None of these

Answer 1

The correct option is C + and $\times$, 4 and 6

Applying
Option A:+ and x, 2 and 4.
$6+2\times 4=6+8=14$
This doesnot make the equation equal to 16
Option B :+ and , 2 and 6
$2+4\times 6=8+6=14$
This doesnot make the equation equal to 16
Option C:+ and , 4 and 6
$4+6\times 2=4+12=16$
Option C is correct
Answer is Option C