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Standard XII

Physics

Thermodynamic Processes

Which one of ...

Question

Which one of the gas dissolves in $H_{2} S O_{4}$ to give oleum?

S O_{2}

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H_{2} S

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S_{2} O

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S O_{3}

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Solution

The correct option is D $S O_{3}$
$S O_{3}$ dissolves in $H_{2} S O_{4}$ to give oleum.
$H_{2} S O_{4} + S O_{3} \to H_{2} S_{2} O_{7}$

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Similar questions

Q. Which gas dissolves in

H_{2} S O_{4}

to give oleum?

Q. One way to express the concentration of oleum (fuming

H_{2} S O_{4}

H_{2} S_{2} O_{7}

, i.e.,

H_{2} S O_{4} + S O_{3}

) is in terms of

%

oleum.

(100 + X) %

oleum means that

X g H_{2} O

reacts with equivalent amount of

S O_{3}

to give oleum.

%

of free

S O_{3}

109 %

oleum is:

Q. Sulphur reacts with conc.

H_{2} S O_{4}

to give a gas A and, it reacts with conc.

H N O_{3}

to give a gas B. A and B respectivley are:

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When

100 g

sample of oleum is diluted with desired weight of

H_{2} O

, the total mass of

H_{2} S O_{4}

will be for example, a oleum bottle labelled as

109 %

H_{2} S O_{4}

, means the

109

g total mass of pure

H_{2} S O_{4}

will be formed when

100

g of oleum is diluted by

9 g

H_{2} O

, which combines with all the free

S O_{3}

to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the

%

of free

S O_{3}

in an oleum that is labelled as

104.5 %

H_{2} S O_{4}

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When 100 g sample of oleum is diluted with desired mass of

H_{2} O

then the total mass of

H_{2} S O_{4}

obtained after dilution is known as % labelling in oleum.
For example, a oleum bottle labelled as '109 %

H_{2} S O_{4}

' means the 109 g total mass of pure

H_{2} S O_{4}

will be formed when 100 g of oleum is diluted by 9 g of

H_{2} O

which combines with all the free

S O_{3}

present in oleum to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the % of free

S O_{3}

in an oleum that is labelled as '104.5 %

H_{2} S O_{4}

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Which one of the gas dissolves in H2SO4 to give oleum?

The correct option is D SO3SO3 dissolves in H2SO4 to give oleum.H2SO4+SO3→H2S2O7

Which one of the gas dissolves in $H_{2} S O_{4}$ to give oleum?

The correct option is D $S O_{3}$
$S O_{3}$ dissolves in $H_{2} S O_{4}$ to give oleum.
$H_{2} S O_{4} + S O_{3} \to H_{2} S_{2} O_{7}$