Which one of the transition metal ions have no unpaired electrons?

^{+ 4}

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^{+ 4}

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^{+ 3}

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^{3 +}

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Solution

The correct option is A Ti $^{+ 4}$
$T i^{+ 4}$ has $d^{0}$ configuration so it has no unpair electron.
$V^{+ 4}$ has $d^{1}$ configuration, have one unpair electron
$V^{+ 3}$ has $d^{2}$ configuration have two unpair electron
and $C r^{3 +}$ has $d^{3}$ configuration have three unpair electron.

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Similar questions

Q. Following are the transition metal ions of

3 d

series:

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

(Atomic numbers:

T i = 22, V = 23, M n = 25, C r = 24)

Answer the following:

(i) Which ion is most stable in an aqueous solution and why?
(ii) Which ion is a strong oxidising agent and why?
(iii) Which ion is colourless and why?

Q. Assertion :The number of unpaired electrons in the following gaseous ions:

M n^{3 +}, C r^{3 +}, V^{3 +}

and

T i^{3 +}

are 4, 3, 2 and 1 respectively. Reason: Among these Cr

^{3 +}

is most stable in aqueous solution.

Calculate the number of unpaired electrons in the following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺. Which one of these is the most stable in aqueous solution?

Q. (a) Following are the transition metal ions of 3d series:

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

(Atomic numbers : Ti = 22, V = 23, Mn = 25, Cr = 24)
Answer the following:
(i) Which ion is most stable in an aqueous solution and why?
(ii) Which ion is a strong oxidising agent and why?
(iii) Which ion is colourless and why?
(b) Complete the following equations:

(i) 2 M n O_{4}^{-} + 16 H^{+} + 5 S^{2 -} \to (i i) K M n O_{4} H e a t - -- \to

Which of the following ion has same number of unpaired electrons as that of $V^{3 +}$ ion?

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Which one of the transition metal ions have no unpaired electrons?

The correct option is A Ti+4Ti+4 has d0 configuration so it has no unpair electron.V+4 has d1 configuration, have one unpair electronV+3 has d2 configuration have two unpair electronand Cr3+ has d3 configuration have three unpair electron.

The correct option is A Ti $^{+ 4}$
$T i^{+ 4}$ has $d^{0}$ configuration so it has no unpair electron.
$V^{+ 4}$ has $d^{1}$ configuration, have one unpair electron
$V^{+ 3}$ has $d^{2}$ configuration have two unpair electron
and $C r^{3 +}$ has $d^{3}$ configuration have three unpair electron.