Which one of these gas is released when Na reacts with cold water?

H_{2}

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C l_{2}

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O_{2}

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H_{2} O

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Solution

The correct option is B $H_{2}$
Reaction of 'Na' with cold water.
$2 N a + H_{2} O \to N a_{2} O + H_{2} ↑$
The reaction stops with forming $N a_{2} O$ . Because, we used cold water. The reaction doesnt continue to form NaOH.

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Similar questions

(C l_{2}, S O_{2}, H_{2} S)

H_{2}

X = C

Y = N a

Z = B r

	Hydride of X	Hydride of Y	Hydride of Z
(A)	Colourless gas insoluble in $H_{2}$	Silver/grey solid, reacts with $H_{2} O$ to form an alkaline solution	Colourless gas form a strong acid in $H_{2} O$
(B)	Colourless liquid, no reaction with $H_{2} O$	Silver/grey solid, forms $H_{2} O$	Ionic solid with formula $Z H$
(C)	Colourless gas found naturally	Does not conduct electricity in the molten state	Colourless gas, reacts with $C l_{2}$
(D)	Non-polar compound reacts with $C l_{2}$ in light	Silver/grey ionic solid with formula $Y H_{2}$	Forms when water is added to phosphorus and element Z

H_{2}

H_{2} O_{2}

H_{2} O

O_{2}

O_{2}

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