The correct options are
B 12 24Mg+β+→13 24Al
C 4 9Be+2 4He→6 12C+n
92 238U→90 234Th+α
In this reaction 92 238U does α decay and 90 234Th is formed. It is natural decay.
12 24Mg+β+→13 24Al
In this reaction nonradioactive Mg atom does β+ and 13 24Al is formed. It is artificial decay.
4 9Be+2 4He→6 12C+n
In this reaction nonradioactive Be atom does 2 4He decay and 6 12C is formed. It is also artificial decay.