Which ones of the following statements are true for given reaction?
4 9Be+1 3H→5 11B+0 1n
Be and 1 3H come together and form 5 11B atom. Thus, it is artificial radioactive decay or fusion. We write number of neutrons in both sides;
4 9Be+1 3H→5 11B+0 1n
5 + 2 =6 + 1
7=7
We can say that number of neutrons in this reaction is conserved