Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

Lithium, 0.45 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Tungston, 1.75 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Lithium, 2.30 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Tungston, 2.75 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{k}) = Δ E - W_{0}$
For maximum value of $(E) k), W_{0}$ should be minimum $W_{0}$ for lithium $= 2.3 e V$
$∴ (E_{k}) = 2.75 - 2.3 = 0.45 e V$ .

Suggest Corrections

Similar questions

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.
$\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}$

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

Q. Which option correctly identifies metal that will produce the most energetic electrons and their energies ?

Q. In photoelectric emission process from a metal of work function 1.8 eV, the kinetic energy of most energetic electrons is 0.5 eV. The corresponding stopping potential is :

Q. In a photo electric emission process from a metal of work function 1.8 eV, the kinetic energy of most energetic electrons is 0.5 eV. The corresponding stopping potential is

Join BYJU'S Learning Program

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

The correct option is A Lithium, 0.45 eVΔE=W0+E;(Ek)=ΔE−W0For maximum value of (E)k),W0 should be minimum W0 for lithium =2.3eV∴(Ek)=2.75−2.3=0.45eV.

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{k}) = Δ E - W_{0}$
For maximum value of $(E) k), W_{0}$ should be minimum $W_{0}$ for lithium $= 2.3 e V$
$∴ (E_{k}) = 2.75 - 2.3 = 0.45 e V$ .