Question

Which option gives proper fraction?

• A. $\frac{1}{3}+\frac{2}{3}$
• B. $\frac{1}{4}+\frac{2}{3}$
• C. $\frac{5}{8}+\frac{2}{8}$
• D. $\frac{1}{1}+\frac{2}{8}$

Answer 1

The correct option is B $\frac{1}{4}+\frac{2}{3}$

The fraction whose numerator is less than the denominator is called a proper fraction.

$\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1$
$\frac{1}{1}:\text{Numerator = Denominator}$
Hence, 1 is not a proper fraction

$\frac{1}{4}+\frac{2}{3}=\frac{3+8}{12}=\frac{11}{12}$
$\frac{11}{12}:\text{Numerator < Denominator}$.
Hence, $\frac{11}{12}$ is a proper fraction.

$\frac{7}{8}+\frac{2}{8}=\frac{7+2}{8}=\frac{9}{8}$
$\frac{9}{8}:\text{Numerator > Denominator}$.
Hence, $\frac{9}{8}$ is not a proper fraction.

$\frac{1}{1}+\frac{2}{8}=\frac{8+2}{8}=\frac{10}{8}$
$\frac{10}{8}:\text{Numerator > Denominator}$.
Hence, $\frac{10}{8}$ is not a proper fraction.

$\therefore$ Option "b" is the correct answer