Which order is correct for the decreasing reactivity to ring monobromination of the following compounds?
(I) $C_{6} H_{5} C H_{3}$
(II) $C_{6} H_{5} C O O H$
(III) $C_{6} H_{6}$
(IV) $C_{6} H_{5} N O_{2}$

I > II > III > IV

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I > III > II > IV

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II> III > IV > I

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III > I > II > IV

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Solution

The correct option is B I > III > II > IV
Carboxylic group and nitro group deactivate the benzene ring towards electrophilic aromatic substitution reactions.
Methyl group activates the benzene ring towards electrophilic aromatic substitution reactions.
The correct order for the decreasing reactivity to ring mono bromination is
$I > I I I > I I > I V$ or $C_{6} H_{5} C H_{3} > C_{6} H_{6} > C_{6} H_{5} C O O H > C_{6} H_{5} N O_{2}$

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Similar questions

C_{6} H_{5} C H_{3} I, C_{6} H_{5} C O O H I I, C_{6} H_{6} I I I, C_{6} H_{5} N O_{2} I V

C_{6} H_{5} C H_{3} I, C_{6} H_{5} C O O H I I, C_{6} H_{6} I I I, C_{6} H_{5} N O_{2} I V

50^{\circ}

The correct order for decreasing stability of the following free radicals is

- S O_{3} H

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