Which pair of following forces will never give resultant force of $2 N$ .

2 N

and

2 N

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1 N

and

1 N

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1 N

and

3 N

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1 N

and

4 N

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Solution

The correct option is D $1 N$ and $4 N$
The triplet $(1 N . 4 N 2 N)$ can't form a triangle since $2 + 1 < 4$ the triangle inequality sates that the sum of any two sides in a triangle must be greater than the third side

So, the $(1 N, 4 N)$ vector pair can't form a $2 N$ resultant vector.
Hence , Option $D$ is the correct answer.

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